Areas Quiz Set 010

Advertisement


Your Score
Correct Answers:
Wrong Answers:
Unattempted:

Question 1

Two concentric circles of radii 11 and 4 cm are drawn on a paper. What is the area of the portion that is inside the outer circle but outside the inner circle?

 A

105π sq. cm.

 B

210π sq. m.

 C

11025π sq. m.

 D

52π sq. m.

Soln.
Ans: a

The required area is difference of the areas of the two circles. π($11^2 - 4^2$) = 105π sq. cm.


Question 2

What is the area of the largest circle that can fit completely inside a square of side 6 meters?

 A

9π sq. m.

 B

18π sq. m.

 C

81π sq. m.

 D

4.5π sq. m.

Soln.
Ans: a

The radius of such a circle is 6/2 = 3 m. So its area = π × 3 × 3 = 9π sq. m.


Question 3

The length and breadth of a rectangle are in the ratio 13 : 2. What is the perimeter if the area is 104 sq. meters?

 A

60 meters.

 B

62 meters.

 C

58 meters.

 D

64 meters.

Soln.
Ans: a

Let L = 13x and B = 2x. We are given (13x × 2x) = 104, which gives x = 2. So perimeter = 2 × ((13 × 2) + (2 × 2)) × = 60 meters.


Question 4

The length and breadth of a rectangle are in the ratio 19 : 7. What is the perimeter if the area is 2128 sq. meters?

 A

208 meters.

 B

210 meters.

 C

206 meters.

 D

212 meters.

Soln.
Ans: a

Let L = 19x and B = 7x. We are given (19x × 7x) = 2128, which gives x = 4. So perimeter = 2 × ((19 × 4) + (7 × 4)) × = 208 meters.


Question 5

The length and breadth of a rectangle are respectively increased by 7% and 4%. What is the % increase in the area?

 A

$11{7/25}$%.

 B

$12{19/24}$%.

 C

$9{14/27}$%.

 D

$13{2/9}$%.

Soln.
Ans: a

If x% and y% is the increase in the dimensions, then the area of a rectangle increases by $(x + y + {xy}/100)$% = $(7 + 4 + {7 × 4}/100)$% = ${282/25}$, which is same as: $11{7/25}$%


buy aptitude video tutorials


Creative Commons License
This Blog Post/Article "Areas Quiz Set 010" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-04-07.

Posted by Parveen(Hoven),
Aptitude Trainer


Advertisement