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### Question

Two of the 36 numbers are 28 and 58, If these two are excluded the average of the remaining 34 numbers is 1 more than the average of all the 36 numbers. What is the average of all the 36 numbers?

**A**

26.

**B**

27.

**C**

25.

**D**

28.

**Soln.**

**Ans: a**

Let the required average be x. Then $36x - (28 + 58) = 34 × (x - 1).$ which gives $36x - 86 = 34 × (x - 1).$ Solving for x we get x = 26.