# Averages Quiz Set 005

### Question 1

In a cricket match of 50 overs a team has to chase a target of 270 runs. During the first 10 overs it has scored at the rate of 3 runs per over. What is the required run rate for the remaining 40 overs?

A

6.

B

7.

C

5.

D

4.

Soln.
Ans: a

The runs already scored = scoring rate × overs = \$3 × 10\$ = 30. Required number of runs = 270 - 30 = 240 in 50 - 10 = 40 overs. Required rate = 240/40 = 6.

### Question 2

The sales(in rupees) of a gift shop for six consecutive days is 2160, 2100, 3234, 3636, 1932 and 4266. What is the overall average sale for these six days?

A

Rs.2888.

B

Rs.2894.

C

Rs.2882.

D

Rs.2900.

Soln.
Ans: a

The total sale on first six days is 2160 + 2100 + 3234 + 3636 + 1932 + 4266 = 17328. The average for 6 days is: 17328/6, which gives Rs. 2888.

### Question 3

The average weight of the 11 bogies of a train increases by 14 Kg when a new bogie replaces a bogie of weight 13 Kg. What is the weight of the new bogie.

A

167.

B

168.

C

166.

D

169.

Soln.
Ans: a

The total increase of weight = 11 × 14 = 154. So the weight of the new bogie = 13 + 154 = 167 Kg.

### Question 4

The cost per unit of a commodity in three successive years is Rs.14/unit, Rs.6/unit and Rs.16/unit. If the annual spending of a family remains fixed, what is the average cost per unit for all the three combined years together?

A

\$9{99/101}\$.

B

12.

C

9.

D

\$7{1/5}\$.

Soln.
Ans: a

Let the annual spending be Rs. M. The catch in this question is that the spending remains fixed, so the consumption varies from year to year. We shall calculate the total consumption first. Let r1, r2 and r3 be the rates for the three successive years. Consumption in first year = M/r1. Similarly, we get M/r2 and M/r3. So total consumption is \$M/{r1} + M/{r2} + M/{r3}\$. Money spent in three years is 3M. So the required average = \${3M}/{M/{r1} + M/{r2} + M/{r3}}\$ which simplifies to \${3r1r2r3}/{r1r2 + r2r3 + r3r1}\$. Putting r1 = 14, r2 = 6, r3 = 16, we get \$9{99/101}\$. You might be wondering why I derived the formula first. The reason is that sometimes it is better to postpone calculations till the end.

### Question 5

The average age of three friends 3 years ago was 31 years. The average age of two them 5 years ago was 19 years. What is the present age of the third friend?

A

54 years.

B

55 years.

C

53 years.

D

52 years.

Soln.
Ans: a

Let the present ages of the three friends be a, b and c. We are given \${(b - 5) + (c - 5)}/2\$ = 19. Which gives b + c = 48. We are also given \${(a - 3) + (b - 3) + (c - 3)}/3\$ = 31, which gives a + b + c = 3 * 31 + 9 = 102. Putting b + c here we get a = 102 - (b + c) = 102 - 48 = 54 years.

This Blog Post/Article "Averages Quiz Set 005" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-04-07.

Posted by Parveen(Hoven),
Aptitude Trainer