# Basic Simplification Quiz Set 001

### Question 1

What is 122 + 345 - 1 × 1116 ÷ 372?

A

464.

B

465.

C

463.

D

466.

Soln.
Ans: a

We have by bodmas 122 + 345 - 1 × 1116 ÷ 372 = 122 + 345 - (1 × (1116 ÷ 372)) = (122 + 345) - (1 × (3)) = (122 + 345) - 3 = 467 - 3 = 464.

### Question 2

What is 447 × 49?

A

21903.

B

21912.

C

21894.

D

21921.

Soln.
Ans: a

This is a multiplication by a number whose units place is 9. Proceed like this: 447 × 49 = 447 × (40 + 9) = 447 × (40 + 10 - 1) = (447 × 40) + (447 × 10) - 447 = 17880 + 4470 - 447 = 21903. The other approach could have been 447 × 49 = 447 × (50 - 1), etc.,

### Question 3

A salesman is on a tour and has Rs. 450 for his expenses. If he exceeds his tour by 15 days, then he has to cut down his daily expenses by Rs. 15. What is the duration of his tour?

A

15 days.

B

17 days.

C

13 days.

D

19 days.

Soln.
Ans: a

Let the duration be x days. We have \$450/x\$ - \$450/{x + 15}\$ = 15. This equation can now be solved, or you can try substituting the options one by one, to obtain x = 15 days.

### Question 4

What is -341 + (-354) - (-393) + 418?

A

116.

B

117.

C

115.

D

118.

Soln.
Ans: a

We have -341 + (-354) - (-393) + 418 = -341 - 354 + 393 + 418 = -(341 + 354) + (393 + 418) = -695 + 811 = 116.

### Question 5

A bag contains equal number of coins each of Rs. 1, 5 and 10. What is the total number of coins in the bag, if the total money is Rs. 368?

A

69.

B

23.

C

67.

D

73.

Soln.
Ans: a

Let there be N coins of each denomination. Then N × (1 + 5 + 10) = 368, which gives N = \$368/16\$, and 3N = 3 × \$368/16\$ = 69.