Discussion of Question with ID = 061 under HCF-and-LCM

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Question

Which is the smallest number which when divided by 15, 12 or 14 leaves 12, 9, 11 as the respective remainders?

A

417.

B

418.

C

416.

D

419.

Soln.
Ans: a

By inspection, the difference between the numbers and their respective remainders is same = 3. The LCM of 15, 12 and 14 = 420. So the required number is 420 - 3 = 417.


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