Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

Which is the least number which must be added to 7347 so that it becomes divisible by 21, 75 and 98?

### Question 2

What is the HCF of (10 × 12), (12 × 16) and (16 × 10)?

**A**

8.

**B**

16.

**C**

4.

**D**

24.

**Soln.**

**Ans: a**

The required HCF is product of the three numbers divided by their LCM. The LCM of 10, 12 and 16 is 240. So the required HCF = ${10 × 12 × 16}/240$ = 8. *Please note that LCM(n1, n2, n3) × HCF(n1 × n2, n2 × n3, n3 × n1) = n1 × n2 × n3.*

### Question 3

The HCF of two numbers is 13. The factors of their LCM are 13, 3 and 43. Which is the greater of the two numbers?

### Question 4

Three cyclists are cycling in a circular track. They, respectively, take 3, 11 and 18 minutes to complete the circle once. After how many minutes will they all again meet at a single point?

### Question 5

Which is the second smallest number, which, when divided by 18 and 90, leaves the remainder 2?

**A**

182.

**B**

92.

**C**

272.

**D**

88.

**Soln.**

**Ans: a**

The LCM of 18 and 90 = 90. All the numbers that leave remainder 2 upon being divided by either of the given two numbers are of the form 90k + 2. When k = 1, we get the smallest number, and k = 2 gives the next required number = 182.

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This Blog Post/Article "HCF and LCM Quiz Set 012" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-05-17.