Percentages Quiz Set 015

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Question 1

If 82 is m% of p, and B is p% of m, then what is B?

 A

82.

 B

92.

 C

72.

 D

102.

Soln.
Ans: a

Let 82 = A, so A = $m/100$ × p = $p/100$ × m. = B, so A and B are same.


Question 2

The service tax is 5%. A person receives a telephone bill amounting to Rs. 630. How much was the bill excluding tax?

 A

Rs. 600.

 B

Rs. 610.

 C

Rs. 590.

 D

Rs. 620.

Soln.
Ans: a

Let the calls be for Rs. x. The total bill is x + 5% of x = ${21x}/20 = 630$, which gives x = Rs. 600.


Question 3

A carton contains 8000 led bulbs, some of them are red, some green and others are blue. How many are green if 3% are red and 5% are blue?

 A

7360.

 B

7460.

 C

7260.

 D

7560.

Soln.
Ans: a

The percentage of green is 100 - (3 + 5) = 92. So number of green bulbs = $92/100$ × 8000 = 7360.


Question 4

The service tax is 5%. A person receives a telephone bill amounting to Rs. 840. How much was the bill excluding tax?

 A

Rs. 800.

 B

Rs. 810.

 C

Rs. 790.

 D

Rs. 820.

Soln.
Ans: a

Let the calls be for Rs. x. The total bill is x + 5% of x = ${21x}/20 = 840$, which gives x = Rs. 800.


Question 5

A number is first increased by 40%. By what percent must it be reduced so as to restore it to its previous value?

 A

$28{4/7}$ %.

 B

$34{1/2}$ %.

 C

$21{4/9}$ %.

 D

$24{5/9}$ %.

Soln.
Ans: a

Let us derive the shortcut formula first, so that you can remember it and use it when the need arises. Suppose the number is 100, and let the increase be x%. The number becomes 100 + x. Let us suppose that it has to be reduced by p% to restore it to 100. Then, (100 + x) - p × $(100 + x)/100$ = 100. We can cancel away 100, and easily simplify it to p = ${100 × x}/{100 + x}$ = ${100 × 40}/{100 + 40}$ = ${200/7}$, which is same as: $28{4/7}$%.


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Creative Commons License
This Blog Post/Article "Percentages Quiz Set 015" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer


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