Discussion of Question with ID = 002 under Pipes-and-Cisterns

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Question

Tap X can fill the tank in 19 mins. Tap Y can empty it in 6 mins. In how many minutes will the tank be emptied if both the taps are opened together when the tank is $13/17$th full of water?

A

$6{12/17}$ mins.

B

$8{3/16}$ mins.

C

$5{2/19}$ mins.

D

$8{13/19}$ mins.

Soln.
Ans: a

1 filled tank can be emptied in ${19 × 6}/{19 - 6}$ mins. So 13/17 can be emptied in ${19 × 6}/{19 - 6}$ × $13/17$ = ${114/17}$, which is same as: $6{12/17}$ mins.


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