Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

The ages of two friends are in the ratio 3:5. What is the age of the younger friend if the sum of their ages is 24 years?

### Question 2

The ages of three friends are in the ratio 19:2:3. What is the age of the youngest friend if the sum of their ages 5 years back was 129 years?

**A**

12 years.

**B**

13 years.

**C**

11 years.

**D**

14 years.

**Soln.**

**Ans: a**

Let the ages of three friends be 19r, 2r and 3r. The youngest of these is 2r. We have been given their sum 5 years back. So (19 + 2 + 3)r - (3 × 5) = 129. Solving, we get r = 6. The youngest is 2 × 6 = 12 years.

### Question 3

The sum of the ages of 12 calves of a whale born at a gap of 8 years is 672. What is the age of the youngest calf?

**A**

12 years.

**B**

13 years.

**C**

11 years.

**D**

14 years.

**Soln.**

**Ans: a**

The ages of the calves are in an AP with d = 8, n = 12, and sum S = 672. We have to find the first term a. We know S = ${n/2} × (2a + (n-1)d)$ Putting the values 672 = ${12/2} × (2a + (12-1)×8)$. Solving, get a = 12 years.

### Question 4

The sum of the ages of 14 calves of a whale born at a gap of 8 years is 924. What is the age of the youngest calf?

**A**

14 years.

**B**

15 years.

**C**

13 years.

**D**

16 years.

**Soln.**

**Ans: a**

The ages of the calves are in an AP with d = 8, n = 14, and sum S = 924. We have to find the first term a. We know S = ${n/2} × (2a + (n-1)d)$ Putting the values 924 = ${14/2} × (2a + (14-1)×8)$. Solving, get a = 14 years.

### Question 5

The sum of ages of two friends is 15, whereas the product of their ages is 54. What is the sum of squares of their ages?

This Blog Post/Article "Problems on Ages Quiz Set 002" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-05-17.