# Problems on Numbers Quiz Set 001

### Question 1

When a two digit number is reversed and added to itself we get 143. The product of the digits of that number is 36. What is the number?

A

49.

B

50.

C

48.

D

51.

Soln.
Ans: a

Let the number be ab. When it is reversed and added to itself we get (10a + b) + (10b + a) = 11 × (a + b). We are given 143 = 11 × (a + b) ⇒ \$a + b = 143 / 11 = 13\$, so the digits are \$a\$ and \$13 - a\$. We are given their product as a × (13 - a) = 36, which is a quadratic expression that can be simplified to \$(a - 4) × (9 - a) = 0\$. So the number could be 49 or 94.

### Question 2

If  \$x/2 = y/19 = z/28\$, then \${x + y + z}/x\$ = ?

A

\$24{1/2}\$.

B

\$25{1/2}\$.

C

\$23{1/2}\$.

D

\$13{3/4}\$.

Soln.
Ans: a

Let \$x/2 = y/19 = z/28\$ = k. Then \${x + y + z}/x\$ is same as \${2k + 19k + 28k}/{2k}\$ which equals \$24{1/2}\$.

\${49/2}\$ is same as \$24{1/2}\$.

### Question 3

The sum of three consecutive integer numbers is 1014. The smallest of the three is?

A

337.

B

338.

C

336.

D

339.

Soln.
Ans: a

Let the numbers be n - 1, n and n + 1. The sum is 3n. We are given 3n = 1014, ⇒ n = \$1014/3\$, i.e., n = 338. So the smallest is 337.

### Question 4

x should be replaced by which minimum number so that 77x7533423 is completely divisible by 3?

A

1.

B

2.

C

4.

D

3.

Soln.
Ans: a

If the above number has to be divisible by 3, the sum of the digits, i.e., 7 + 7 + x + 7 + 5 + 3 + 3 + 4 + 2 + 3, should be divisible by 3. So we can see that \$x + 41\$ should be divisible by 3. By inspection, x = 1.

### Question 5

The sum of two numbers is 30. Their product is 161. One of the two numbers is?

A

23.

B

24.

C

22.

D

25.

Soln.
Ans: a

Let the numbers be \$a\$ and \$30 - a\$. We are given their product as a × (30 - a) = 161, which is a quadratic expression that can be simplified to \$(a - 23) × (7 - a) = 0\$. So the numbers could be 23 and 7.

This Blog Post/Article "Problems on Numbers Quiz Set 001" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer