# Problems on Numbers Quiz Set 002

### Question 1

14 times the middle of three consecutive even numbers is 160 more than 11 times the smallest of the three numbers. What is the middle number?

A

46.

B

47.

C

45.

D

48.

Soln.
Ans: a

This is the general solution. Let the numbers be 2n - 2, 2n and 2n + 2. We are given 14 × 2n = 160 + 11 × (2n - 2).
⇒ 14 × 2n = 160 + 11 × 2n - 11 × 2.
⇒ 2n × (14 - 11) = 160 - 11 × 2, so 2n = \${160 - 11 × 2}/{14 - 11} = 46\$

### Question 2

If 1 of a number is 10, what is \${3/8}\$ of that number?

A

\$3{3/4}\$.

B

\$6{1/3}\$.

C

\$1{5/6}\$.

D

\$4{1/2}\$.

Soln.
Ans: a

Let the number be N. Then it is given that 1 x N = 10. ⇒ N = 10 X 1. ⇒ \${3/8}\$ x N = \${3/8}\$ x 10 X 1 = \${15/4}\$.

\${15/4}\$ is same as \$3{3/4}\$.

### Question 3

What is x in \$1{19/x}\$ × \$1{7/8}\$ = \$2{9/23}\$?

A

69.

B

70.

C

68.

D

71.

Soln.
Ans: a

We can see that \$1{19/x}\$ = \${55/23}\$ × \${8/15}\$. ⇒ \${1x + 19}/x\$ = \${88/69}\$ ⇒ x = 69.

### Question 4

The sum of three consecutive even integer numbers is 2556. The middle among the three is?

A

852.

B

853.

C

851.

D

854.

Soln.
Ans: a

Let the numbers be 2n - 2, 2n and 2n + 2. The sum is 6n = 3 x 2n = 3 x middle. We are given 3 x middle = 2556, ⇒ middle = \$2556/3\$, i.e., middle = 852.

### Question 5

When a two digit number is reversed and added to itself we get 110. The product of the digits of that number is 21. What is the number?

A

73.

B

74.

C

72.

D

75.

Soln.
Ans: a

Let the number be ab. When it is reversed and added to itself we get (10a + b) + (10b + a) = 11 × (a + b). We are given 110 = 11 × (a + b) ⇒ \$a + b = 110 / 11 = 10\$, so the digits are \$a\$ and \$10 - a\$. We are given their product as a × (10 - a) = 21, which is a quadratic expression that can be simplified to \$(a - 7) × (3 - a) = 0\$. So the number could be 73 or 37.

This Blog Post/Article "Problems on Numbers Quiz Set 002" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer