Problems on Numbers Quiz Set 002

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Question 1

14 times the middle of three consecutive even numbers is 160 more than 11 times the smallest of the three numbers. What is the middle number?

 A

46.

 B

47.

 C

45.

 D

48.

Soln.
Ans: a

This is the general solution. Let the numbers be 2n - 2, 2n and 2n + 2. We are given 14 × 2n = 160 + 11 × (2n - 2).
⇒ 14 × 2n = 160 + 11 × 2n - 11 × 2.
⇒ 2n × (14 - 11) = 160 - 11 × 2, so 2n = ${160 - 11 × 2}/{14 - 11} = 46$


Question 2

If 1 of a number is 10, what is ${3/8}$ of that number?

 A

$3{3/4}$.

 B

$6{1/3}$.

 C

$1{5/6}$.

 D

$4{1/2}$.

Soln.
Ans: a

Let the number be N. Then it is given that 1 x N = 10. ⇒ N = 10 X 1. ⇒ ${3/8}$ x N = ${3/8}$ x 10 X 1 = ${15/4}$.

${15/4}$ is same as $3{3/4}$.


Question 3

What is x in $1{19/x}$ × $1{7/8}$ = $2{9/23}$?

 A

69.

 B

70.

 C

68.

 D

71.

Soln.
Ans: a

We can see that $1{19/x}$ = ${55/23}$ × ${8/15}$. ⇒ ${1x + 19}/x$ = ${88/69}$ ⇒ x = 69.


Question 4

The sum of three consecutive even integer numbers is 2556. The middle among the three is?

 A

852.

 B

853.

 C

851.

 D

854.

Soln.
Ans: a

Let the numbers be 2n - 2, 2n and 2n + 2. The sum is 6n = 3 x 2n = 3 x middle. We are given 3 x middle = 2556, ⇒ middle = $2556/3$, i.e., middle = 852.


Question 5

When a two digit number is reversed and added to itself we get 110. The product of the digits of that number is 21. What is the number?

 A

73.

 B

74.

 C

72.

 D

75.

Soln.
Ans: a

Let the number be ab. When it is reversed and added to itself we get (10a + b) + (10b + a) = 11 × (a + b). We are given 110 = 11 × (a + b) ⇒ $a + b = 110 / 11 = 10$, so the digits are $a$ and $10 - a$. We are given their product as a × (10 - a) = 21, which is a quadratic expression that can be simplified to $(a - 7) × (3 - a) = 0$. So the number could be 73 or 37.


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Creative Commons License
This Blog Post/Article "Problems on Numbers Quiz Set 002" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer


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