Problems on Numbers Quiz Set 012

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Question 1

x should be replaced by which minimum number so that 99938x3687 is completely divisible by 9?

 A

1.

 B

2.

 C

4.

 D

3.

Soln.
Ans: a

If the above number has to be divisible by 9, the sum of the digits, i.e., 9 + 9 + 9 + 3 + 8 + x + 3 + 6 + 8 + 7, should be divisible by 9. So we can see that $x + 62$ should be divisible by 9. By inspection, x = 1.


Question 2

If $5{3/4}$ of a number is 3, what is ${3/14}$ of that number?

 A

${18/161}$.

 B

$1{19/160}$.

 C

$2{14/163}$.

 D

$3{12/163}$.

Soln.
Ans: a

Let the number be N. Then it is given that $5{3/4}$ x N = 3. ⇒ N = 3 X ${4/23}$. ⇒ ${3/14}$ x N = ${3/14}$ x 3 X ${4/23}$ = ${18/161}$.

${23/4}$ is same as $5{3/4}$.


Question 3

How many odd numbers are there between -1386 and 814?

 A

1100.

 B

1101.

 C

1099.

 D

1102.

Soln.
Ans: a

Odd numbers are in an AP. First term $a = -1385$, common difference $d = 2$, the last term $t_n$ is given as 813. By the AP formula, $813 = -1385 + (n - 1) × 2$ ⇒ $n = 1 + {{813 - (-1385)}/2} = 1100$.


Question 4

What is the digit at units place: 7575 × 1390 × 9505?

 A

0.

 B

1.

 C

3.

 D

2.

Soln.
Ans: a

The digit at units place = (last digit of 7575) × (last digit of 1390) × (last digit of 9505) = 5 × 0 × 5 = 0, which = 0.


Question 5

The difference between a two digit number and the one obtained by reversing its digits is 72. If one of the digits is 0, what is the other?

 A

8.

 B

9.

 C

10.

 D

11.

Soln.
Ans: a

Let the numbers be a and b. ab = 10a + b, and ba = 10b + a. The difference is 10a + b - (10b + a) = 9(a - b). It is given that 9(a - b) = 72, ⇒ a - b = $72/9$ = 8, ⇒ the difference between the digits is 8. If one of the digits is 0, the other can be 8.


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Creative Commons License
This Blog Post/Article "Problems on Numbers Quiz Set 012" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-04-07.

Posted by Parveen(Hoven),
Aptitude Trainer


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