# Problems on Numbers Quiz Set 020

### Question 1

The sum of three consecutive odd integer numbers is -2313. The middle among the three is?

A

-771.

B

-770.

C

-768.

D

-769.

Soln.
Ans: a

Let the numbers be 2n - 3, 2n - 1 and 2n + 1. The sum is 3(2n - 1) = 3 x middle. We are given 3 x middle = -2313, ⇒ middle = \$-2313/3\$, i.e., middle = -771.

### Question 2

What is the digit at units place: 1626 × 1947 × 8850?

A

0.

B

1.

C

3.

D

2.

Soln.
Ans: a

The digit at units place = (last digit of 1626) × (last digit of 1947) × (last digit of 8850) = 6 × 7 × 0 = 0, which = 0.

### Question 3

x should be replaced by which minimum number so that 4618521x98 is completely divisible by 3?

A

1.

B

2.

C

4.

D

3.

Soln.
Ans: a

If the above number has to be divisible by 3, the sum of the digits, i.e., 4 + 6 + 1 + 8 + 5 + 2 + 1 + x + 9 + 8, should be divisible by 3. So we can see that \$x + 44\$ should be divisible by 3. By inspection, x = 1.

### Question 4

If  \$x/7 = y/19 = z/24\$, then \${x + y + z}/x\$ = ?

A

\$7{1/7}\$.

B

\$9{1/2}\$.

C

\$4{7/9}\$.

D

\$7{8/9}\$.

Soln.
Ans: a

Let \$x/7 = y/19 = z/24\$ = k. Then \${x + y + z}/x\$ is same as \${7k + 19k + 24k}/{7k}\$ which equals \$7{1/7}\$.

\${50/7}\$ is same as \$7{1/7}\$.

### Question 5

The sum of three consecutive integer numbers is 696. The smallest of the three is?

A

231.

B

232.

C

230.

D

233.

Soln.
Ans: a

Let the numbers be n - 1, n and n + 1. The sum is 3n. We are given 3n = 696, ⇒ n = \$696/3\$, i.e., n = 232. So the smallest is 231.