# Ratio and Proportion Quiz Set 005

### Question 1

A bag contains 25p, 10p and 5p coins in the ratio 11 : 2 : 8. How many 25 paise coins are there if the total amount is Rs. 67?

A

220.

B

222.

C

218.

D

224.

Soln.
Ans: a

Let the total number of coins be 11x, 2x and 8x. Please note that 25p = Rs. 1/4, 10p = Rs. 1/10, 5p = Rs. 1/20, so they add to x × \$(11/4 + 2/10 + 8/20)\$ = 67. LCM of 4, 10 and 20 is 20, multiplying both sides by 20 we have x × \$(11 × 5 + 2 × 2 + 8)\$ = 67 × 20, which is x × \$(55 + 4 + 8)\$ = 67 × 20, solving for x we get x = 20, so 25p coins = 20 × 11 = 220.

### Question 2

A sum of Rs. 9900 is to be divided among three partners, P, Q and R, in the ratio 6 : 2 : 3. How much does Q get?

A

Rs. 1800.

B

Rs. 1802.

C

Rs. 1798.

D

Rs. 1804.

Soln.
Ans: a

The share of Q is in the ratio like this: \$2/{6 + 2 + 3} × 9900\$ = Rs. 1800.

### Question 3

The ratio of shares of three friends in Rs. 1200 are in an A.P.(arithmtic progression). What is the share of the friend who is neither the richest, nor the poorest?

A

Rs. 400.

B

Rs. 404.

C

Rs. 396.

D

Rs. 408.

Soln.
Ans: a

Let the shares be in the ratio a - d : a : a + d. The value of the middle item is \$a/{(a - d) + a + (a + d)}\$ × 1200 = \$a/{3a}\$ × 1200 = \$1200/3\$ = Rs. 400.

### Question 4

What is x, if 42 : x :: 3 : 2?

A

28.

B

32.

C

24.

D

36.

Soln.
Ans: a

We have \$42/x = 3/2\$, which gives x = \${42 × 2}/3\$ = 28.

### Question 5

A bag contains 25p, 10p and 5p coins in the ratio 6 : 9 : 11. How many 25 paise coins are there if the total amount is Rs. 59?

A

120.

B

122.

C

118.

D

124.

Soln.
Ans: a

Let the total number of coins be 6x, 9x and 11x. Please note that 25p = Rs. 1/4, 10p = Rs. 1/10, 5p = Rs. 1/20, so they add to x × \$(6/4 + 9/10 + 11/20)\$ = 59. LCM of 4, 10 and 20 is 20, multiplying both sides by 20 we have x × \$(6 × 5 + 9 × 2 + 11)\$ = 59 × 20, which is x × \$(30 + 18 + 11)\$ = 59 × 20, solving for x we get x = 20, so 25p coins = 20 × 6 = 120.