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### Question 1

An investor puts an amount of Rs. 3200 in a simple interest scheme. If it amounts to Rs. 4640 in 9 years @5%, what would it had amounted to had the rate been 2% more?

### Question 2

A sum of Rs. 1300 is split into two parts. The first part is invested at 12% p.a. and the second at 4% p.a. What is the amount invested at 12% if the total simple interest at the end of 4 years is Rs. 368?

**A**

Rs. 500.

**B**

Rs. 600.

**C**

Rs. 400.

**D**

Rs. 700.

**Soln.**

**Ans: a**

Let the amount x be invested at r1% and remaining (P - x) at r2%, and let the sum of interests be I. Then, I = ${x × r_1 × 4}/100$ + ${(P - x) × r_2 × 4}/100$, which simplifies to 100I = 4 × ($x × (r_1 - r_2) + P × r_2$). Putting r_{1} = 12, r_{2} = 4, P = 1300, I = 368, we get x = Rs. 500.

### Question 3

What is the interest on Rs. 7500 @6% for 73 days starting from Jan 1, 2001?

### Question 4

Mr. X borrowed Rs. 900 from Mr. Y on simple interest @2% for 19 years. He then adds an amount x to it and lends it to Mr. Z @11% for the same duration. What is x if he gains Rs. 2584?

### Question 5

A certain amount is split into two parts. The first part is invested at 8% p.a. and the second at 4% p.a. What is the total amount if the total simple interest at the end of 3 years is Rs. 312, and if the amount invested at 8% is Rs. 1800?

**A**

Rs. 800.

**B**

Rs. 900.

**C**

Rs. 700.

**D**

Rs. 1000.

**Soln.**

**Ans: a**

Let the amount x be invested at r1% and remaining (P - x) at r2%, and let the sum of interests be I. Then, I = ${x × r_1 × 3}/100$ + ${(P - x) × r_2 × 3}/100$, which simplifies to 100I = 3 × ($x × (r_1 - r_2) + P × r_2$). Putting r_{1} = 8, r_{2} = 4, x = 1800, I = 312, we get P = Rs. 800.

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This Blog Post/Article "Simple Interest Quiz Set 017" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-04-07.