Time and Work Quiz Set 001

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Question 1

A, B and C can independently complete a work in 5, 15 and 13 days respectively. B and C start the work together, but A joins them after 2 days. In how many days will the work be completed?

 A

$4{5/67}$ days.

 B

$5{5/67}$ days.

 C

$6{5/67}$ days.

 D

$7{5/67}$ days.

Soln.
Ans: a

Use the shortcut formula. If A, B, C can independently complete the job in x, y and z days, and A joins after n days, the work is completed in ${xyz}/{xy + yz + zx}$ × $(1 + n/x)$ days. Putting the various values x = 5, y = 15, z = 13, n = 2, and simplifying, we get ${273/67}$, which is same as: $4{5/67}$.


Question 2

A, B and C complete a work in 6, 4 and 5 days respectively. All three of them start the work together, but A leaves the work after 2 days, and B leaves the work after 1 days. In how many days will the work be completed?

 A

$2{1/12}$ days.

 B

$3{1/12}$ days.

 C

$4{1/12}$ days.

 D

$5{1/12}$ days.

Soln.
Ans: a

Use the shortcut formula. If A, B, C can independently complete the job in x, y and z days, and A leaves after n days, and B after m days, the work is completed in z × $(1 - n/x - m/y)$ days. Putting the various values x = 6, y = 4, z = 5, n = 2, m = 1, and simplifying, we get ${25/12}$, which is same as: $2{1/12}$.


Question 3

A can do a piece of work in 39 days. B is 30% more efficient than A. In how many days will they complete the work if they work together?

 A

$16{22/23}$ days.

 B

17 days.

 C

$17{1/23}$ days.

 D

$17{2/23}$ days.

Soln.
Ans: a

Let us first calculate the one day work of B. One day work of A is given as $1/39$. If B is 30% efficient, then one day work of B is $1/39$ × $130/100$ = $1/30$. Putting x = 39 and y = 30 in the shortcut method, we get ${xy}/{x + y}$ = ${390/23}$, which is same as: $16{22/23}$.


Question 4

6 men and 4 women finish a job in 32 days. In how many days will 8 women and 12 men finish that job?

 A

16.

 B

15.

 C

17.

 D

18.

Soln.
Ans: a

Since the work force is being doubled proportionately, the time is halved = 16 days.


Question 5

If 56 men can do a task in 16 days, how many men are required to complete the task in 7 days?

 A

7.

 B

8.

 C

6.

 D

10.

Soln.
Ans: a

If m1 men can do a task in d1 days, and m2 in d2, then we must have m1 × d1 = m2 × d2. Putting m1 = 56, d1 = 16 and d2 = 7, we get m2 = 128.


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This Blog Post/Article "Time and Work Quiz Set 001" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer


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