Time and Work Quiz Set 006

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Question 1

A can do a piece of work in 14 days. B is 40% more efficient than A. In how many days can B complete that work?

 A

10 days.

 B

11 days.

 C

9 days.

 D

12 days.

Soln.
Ans: a

Let us first calculate the one day work of B. One day work of A is given as $1/14$. If B is 40% efficient, then one day work of B is $1/14$ × $140/100$ = $1/10$. Which gives 10 days as the answer.


Question 2

A, B and C can independently complete a work in 5, 15 and 16 days respectively. First C starts the work, then A joined after 7 days, and B after 6 days. In how many days was the work completed?

 A

$8{40/79}$ days.

 B

$9{40/79}$ days.

 C

$10{40/79}$ days.

 D

$11{40/79}$ days.

Soln.
Ans: a

Use the shortcut formula. If A, B, C can independently complete the job in x, y and z days, and A joins after n days, and B joins after m days, the work is completed in ${xyz}/{xy + yz + zx}$ × $(1 + n/x + m/y)$ days. Putting the various values x = 5, y = 15, z = 16, n = 7, m = 6, and simplifying, we get ${672/79}$, which is same as: $8{40/79}$.


Question 3

If 30 men can do a task in 54 days if they work 12 hours per day, how many men are required to complete the task in 10 days if they work 9 hours?

 A

216.

 B

217.

 C

215.

 D

219.

Soln.
Ans: a

If m1 men can do a task in d1 days by working h1 hours per day, and m2 in d2 days by working h2 hours per day, then we must have m1 × d1 × h1 = m2 × d2 × h2. Putting m1 = 30, d1 = 54, h1 = 12, d2 = 10, and h2 = 9 we get m2 = 216.


Question 4

A can harvest a field in 16 days. B can do the same work in 14 days. C can do the same work in 5 days. In how many days will they together harvest the field?

 A

$2{186/187}$ days.

 B

$3{186/187}$ days.

 C

$4{186/187}$ days.

 D

$5{186/187}$ days.

Soln.
Ans: a

Putting x = 16, y = 14 and z = 5 in the shortcut method, we get ${xyz}/{xy + zy + zx}$ = ${560/187}$, which is same as: $2{186/187}$.


Question 5

If 14 men can do a task in 18 days, how many men are required to complete the task in 7 days?

 A

7.

 B

8.

 C

6.

 D

10.

Soln.
Ans: a

If m1 men can do a task in d1 days, and m2 in d2, then we must have m1 × d1 = m2 × d2. Putting m1 = 14, d1 = 18 and d2 = 7, we get m2 = 36.


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This Blog Post/Article "Time and Work Quiz Set 006" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-05-17.

Posted by Parveen(Hoven),
Aptitude Trainer


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