(solved)Question 3.29 of NCERT Class XI Chemistry Chapter 3

Write the general outer electronic configuration of s-, p-, d- and f- block elements.

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Parveen,

Question 3.29
NCERT Class XI Chemistry

Write the general outer electronic configuration of s-, p-, d- and f- block elements.

Solution in Detail
(video solution below this)

$\displaystyle \underline{\underline{\text{s-block}}}$

Group I has $\displaystyle ns^1$ and Group II has $\displaystyle ns^2$

hence, general config is $\displaystyle ns^{1-2}$

$\displaystyle \underline{\underline{\text{d-block}}}$

The general configuration is $\displaystyle ns^{0-2} (n - 1)d^{1-10}$

The d-subshell starts filling after $\displaystyle ns^2$. The expected configuration is $\displaystyle ns^2 (n - 1)d^{1-10}$. But due to exchange energy stabilization, s electrons [0, 1 or both 2] move to the d sub-shell so that d is fully filled or half-filled. Hence, the general configuration becomes as per written above.

Ex. 1: [Z = 29] Cu $\displaystyle \text{[Ar]}4s^13d^{10}$.

Ex. 2: [Z = 46] Palladium $\displaystyle \text{[Kr]}5s^04d^{10}$.

$\displaystyle \underline{\underline{\text{f-block}}}$

The general configuration is $\displaystyle ns^2 (n - 2)f^{1-14} (n - 1)d^{0-2}$

$\displaystyle \underline{\underline{\text{p-block}}}$

The $\displaystyle ns^2$ subshell, followed by the inner $\displaystyle (n-2)f^{14}$, $\displaystyle (n-1)d^{10}$ subshells [wherever available] are fully filled, and now np -subshell starts filling.

G13 $\displaystyle ns^2np^1$ . . . G18 $\displaystyle ns^2np^{6}$

hence, the general configuration is $\displaystyle ns^{2}np^{1-6}$

Video Explanation

Please watch this youtube video for a quick explanation of the solution:

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