Question 1.7
NCERT Class XI Chemistry
How much copper can be obtained from 100 g of copper sulphate (CuSO4)?
Solution in Brief
Molar mass of CuSO4 = 63.54(Cu) + 32.06(S) + (16.00(O) x 4) = 159.60 g/mol. Hence, 159.60 g of copper sulphate contains 63.54 g copper. Therefore, 100 g of CuSO4 will give (63.54/159.60) x 100 = 39.8 grams copper (Answer).
Video Explanation
(detailed solution given after this video)
Please watch this youtube video for a quick explanation of the solution:
Solution in Detail
Atomic masses of Cu = 63.54u, S = 32.06u and O = 16.00u.
$ \begin{aligned} &\underline{\text{Molar Mass of CuSO}_4}\\ &= 63.54 + 32.06 + (16.00 \times 4)\\ &=159.60 \text{ g/mol}\\\\ &\therefore 159.60 \text{ g CuSO}_4 \text{ gives } 63.54 \text{ g Cu}\\\\ &\therefore 100 \text{ g CuSO}_4 \equiv \frac{63.54}{159.60} \times 100 \text{ g}\\\\ &=39.8\text{ g}\:\underline{Ans} \end{aligned} $
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