Question 3.6
NCERT Class XI Chemistry
Write the atomic number of the element present in the third period and seventeenth group of the periodic table.
Solution in Detail
(video solution below this)
P3 and G17 $\displaystyle \implies $ config ends in 3p5
Noble gas in previous, i.e., P2 is Ne
by aufbau config is [Ne] 3s23p5
$\displaystyle \implies $ Z = 10 [Ne] + 2 + 5 = 17
$\displaystyle \implies $ element is Chlorine (Cl) $\displaystyle \underline{Ans}$
Video Explanation
Please watch this youtube video for a quick explanation of the solution:
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