(solved)Question 5 SSC-CGL 2019 June 13 Shift 1

If 2 sinθ = 5 cosθ, then (sinθ + cosθ)/(sinθ - cosθ)=?
(Rev. 20-Jan-2024)

Categories | About Hoven's Blog

Parveen,

Question 5
SSC-CGL 2019 June 13 Shift 1

If 2 sinθ = 5 cosθ, then (sinθ + cosθ)/(sinθ - cosθ) = ?

  1. 5/3
  2. 9/5
  3. 2/3
  4. 7/3

Solution in Short

2 sinθ = 5 cosθ gives tanθ = 5/2. To find (sinθ + cosθ)/(sinθ - cosθ) divide numerator and denominator by cosθ to get (tanθ + 1)/(tanθ - 1) = (5/2 + 1)/(5/2 - 1) = 7/3 answer!

Solution in Detail

Given $\displaystyle 2\sin \theta = 5 \cos \theta$

$\displaystyle \implies \frac{\sin \theta}{\cos \theta} = \frac 52\text{ . . . (1)}$

Remember componendo dividendo?

If $\displaystyle \frac xy = \frac pq \implies \frac{x + y}{x - y} = \frac{p + q}{p - q}$

$\displaystyle \therefore \text{ from (1) } \frac{\sin \theta + \cos \theta}{\sin \theta - \cos \theta} = \frac{5 + 2}{5 - 2}$

$\displaystyle \implies \frac 73 \:\underline{Ans}$

Creative Commons License
This Blog Post/Article "(solved)Question 5 SSC-CGL 2019 June 13 Shift 1" by Parveen is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.