(solved)Question 13 SSC-CGL 2020 March 4 Shift 3

If 7cos²θ + 3sin²θ = 6, then (cot²θ + sec²θ )/(tan²θ - sin²θ) = ?
(Rev. 20-Jan-2024)

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Parveen,

Question 13
SSC-CGL 2020 Mar 4 Shift 3

If 7cos²θ + 3sin²θ = 6, then (cot²θ + sec²θ )/(tan²θ - sin²θ) = ?

Solution in Short

Putting cos²θ = 1 - sin²θ in the given equation, we can easily get sinθ = 1/2, which gives θ = 30°. Then cot²θ = 3, sec²θ = 4/3, tan²θ = 1/3 can be used in the required expression to get 52 answer!


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