Question 2.11
NCERT Class XI Chemistry
A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second.
Video Explanation
(detailed solution given after this video)
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Solution in Detail
by Planck's equation energy E of n quanta
$\displaystyle E = n \times \frac{hc}{\lambda}$
$\displaystyle \implies n = \frac{E \lambda}{hc}$
Energy by bulb = 25 W = 25 J/s
$\displaystyle \therefore n = \frac{25 \text{(J/s)} \times (0.57 \times 10^{-6} \text{ (m)})}{6.6 \times 10^{-34}\text{ (Js)} \times 3 \times 10^8\text{ m/s}}$
$\displaystyle = 7.19 \times 10^{19} \text{quanta/s}$
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