(solved)Question 12 SSC-CGL 2020 March 3 Shift 1

Re 4300 becomes Re 4644 when invested at SI for 2 years. What will Re 10104 become when invested for 5 years at the same plan?
(Rev. 31-Oct-2024)

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Parveen,

Question 12
SSC-CGL 2020 Mar 3 Shift 1

Re 4300 becomes Re 4644 when invested at SI for 2 years. What will Re 10104 become when invested for 5 years at the same plan?

Solution in Brief

If simple rate of interest remains same, money-years are directly proportional to the interest earned.

Given that money-years of (4300 x 2 = 8600) yield an interest of (4644 - 4300) = 344 Rs.

By unitary method, (10104 x 5) will yield an interest of 344/8600 x (10104 x 5) = 2020.8, giving the final amount as 10104 + 2020.8 = 12124.8 Rs. ans!

Solution in Detail

for case I: I1=46444300=344\displaystyle I_1 = 4644 - 4300 = 344

Also, P1=4300\displaystyle P_1 = 4300, T1=2\displaystyle T_1 = 2 yrs.

By SI formula I=P×R×T\displaystyle I = P \times R \times T

344=4300×R×2 . . . (1)\displaystyle \therefore 344 = 4300 \times R \times 2\text{ . . . (1)}

for case II: P2=10104\displaystyle P_2 = 10104, T2=5\displaystyle T_2 = 5

I2=10104×R×5 . . . (2)\displaystyle \therefore I_2 = 10104 \times R \times 5\text{ . . . (2)}

Divide (2) by (1) to get

I2344=10104×R×54300×R×2\displaystyle \frac{I_2}{344} = \frac{10104 \times R \times 5}{4300 \times R \times 2}

    I2=2020.8\displaystyle \implies I_2 = 2020.8

\displaystyle \therefore amount = 10104+2020.8\displaystyle 10104 + 2020.8

=Rs. 12124.8Ans\displaystyle = \text{Rs. }12124.8\:\underline{ Ans}

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