Question 2.24
NCERT Class XI Chemistry
What is the lowest value of n that allows g orbitals to exist?
Solution in Detail
(video solution below this)
Given orbital g (l = 4) just exists
Hence, s, p, d and f must also exist
$\displaystyle \therefore $possible l = 0, 1, 2, 3, 4
by quantum theory $\displaystyle l$ = 0, 1 . . . (n - 1)
comparing, $\displaystyle \implies (n - 1) = 4$
$\displaystyle \implies n = 5$
but g will exist for higher n also
$\displaystyle \therefore \text{g exists if }n \geqslant 5\:\underline{Ans}$
Video Explanation
Please watch this youtube video for a quick explanation of the solution:
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