### Question 2.24

NCERT Class XI Chemistry

What is the lowest value of n that allows g orbitals to exist?

### Solution in Detail

(video solution below this)

Given orbital g (l = 4) just exists

Hence, s, p, d and f must also exist

$\displaystyle \therefore $possible l = 0, 1, 2, 3, 4

by quantum theory $\displaystyle l$ = 0, 1 . . . (n - 1)

comparing, $\displaystyle \implies (n - 1) = 4$

$\displaystyle \implies n = 5$

but g will exist for higher n also

$\displaystyle \therefore \text{g exists if }n \geqslant 5\:\underline{Ans}$

### Video Explanation

Please watch this youtube video for a quick explanation of the solution:

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