(solved)Question 2.31 of NCERT Class XI Chemistry Chapter 2

How many electrons in an atom may have the following quantum numbers? (a) n = 4, ms = - ½ (b) n = 3, l = 0

Categories | About Hoven's Blog

Parveen,

Question 2.31
NCERT Class XI Chemistry

How many electrons in an atom may have the following quantum numbers? (a) n = 4, ms = - ½ (b) n = 3, l = 0

Note: Q 2.26, 2.27, 2.28, 2.29 and 2.30 are simple enough. So they have been skipped. Please write an email to us if you face any difficulty with any of them.

Solution in Detail
(video solution below this)

$\displaystyle \underline{\underline{\text{Part (a)}}}$

Total orbitals = $\displaystyle n^2$

Given: n = 4

$\displaystyle \therefore \text{ orbitals } = 4^2 = 16$

but each orbital can contain only one electron of spin -½

$\displaystyle \therefore $ total electrons $\displaystyle = 16\:\underline{Ans}$

$\displaystyle \underline{\underline{\text{Part (b)}}}$

Given n = 3, l = 0

but l = 0 means sub-shell = s

$\displaystyle \therefore $ orbital is 3s

but subshell s can have max. 2 electrons

$\displaystyle \therefore 2 \:\underline{Ans}$

Video Explanation

Please watch this youtube video for a quick explanation of the solution:

Creative Commons License
This Blog Post/Article "(solved)Question 2.31 of NCERT Class XI Chemistry Chapter 2" by Parveen is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.